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Proof step 2 from proof uint2bits-sgn-2pot-01 (previous step)

0 < j, ∀ i. 0 ≤ i → j ≠ 2 ^ i ⊦ sgn(bitsinvert(uint2bits(j)) +1) = bitsinvert(uint2bits(j)) +1

Lemma uint2bits-sgn-2pot