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Proof step 5 from proof uint2bits-sgn-2pot (previous step)

uint2bits(j) = false ' + true ' + bits, false ∈ uint2bits(j), 0 < j, ∀ i. ¬ i < 0 → j ≠ 2 ^ i ⊦ sgn(bitsinvert(uint2bits(j)) +1) = bitsinvert(uint2bits(j)) +1

User applied rule insert equation

And obtained the following new goals

Proof step 6:
uint2bits(j) = false ' + true ' + bits, false ∈ false ' + true ' + bits, 0 < j, ∀ i. ¬ i < 0 → j ≠ 2 ^ i ⊦ sgn(bitsinvert(false ' + true ' + bits) +1) = bitsinvert(false ' + true ' + bits) +1

Rule argument

pos: left 1 flags:

Proof step 5 from proof uint2bits-sgn-2pot (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information