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Proof step 1 from proof uint2bits-sgn-first (conclusion)

⊦ 0 < j → sgn(bitsinvert(uint2bits(j)) +1) ≠ false + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
sgn(bitsinvert(uint2bits(j)) +1) = false ' + bits, 0 < j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ boolvar + bits = boolvar ' + bits;