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Proof step 13 from proof uint2bits-sgn (previous step)

bits0 = boolvar + bits ∧ bits0 ≠ [], uint2bits(i) = false ' + bits0, boolvar, false ∈ uint2bits(i), 0 < i ⊦ sgn(uint2bits(i)) = uint2bits(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
uint2bits(i) = false ' + true ' + bits, 0 < i, false ∈ uint2bits(i) ⊦ sgn(uint2bits(i)) = uint2bits(i)

Rule argument

Additional information

Used simplifier rules: uint2bits-onein: ⊦ 0 < j → true ∈ uint2bits(j);% ⊦ bits = bits0 + boolvar ' + bits1 → boolvar ∈ bits; (forward)% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;