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Proof step 2 from proof uint2bits-sgn (previous step)

0 < i ⊦ sgn(uint2bits(i)) = uint2bits(i)

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → ¬ uint2bits(i).first
Proof step 4:
0 ≤ i → ¬ uint2bits(i).first, 0 < i ⊦ sgn(uint2bits(i)) = uint2bits(i)

Rule argument

name: uint2bits-first subst: [i] → [i]

Additional information

Used terms: i