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Proof step 6 from proof uint2bits-sgn (previous step)

uint2bits(i) = boolvar + bits ∧ uint2bits(i) ≠ [], 0 < i ⊦ sgn(uint2bits(i)) = uint2bits(i), boolvar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
uint2bits(i) = false ' + bits, 0 < i, false ∈ uint2bits(i) ⊦ sgn(uint2bits(i)) = uint2bits(i)

Rule argument

Additional information

Used simplifier rules: uint2bits-empty: 0 ≤ i ⊦ uint2bits(i) ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i;% ⊦ boolvar + bits = boolvar ' + bits;