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Proof step 19 from proof uint2bits-succ (previous step)

j % 2 = 0, 0 ≤ j, 0 < j, ∀ j0. i→n(j0) < i→n(j) → 0 ≤ j0 → uint2bits(j0 + 1) = sgn(false ' + uint2bits(j0) +1) ⊦ uint2bits(j / 2) + true ' = sgn(false ' + uint2bits(j / 2) + true '), j = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
boolvar ↔ ¬ boolvar0 ⊦ sgn(boolvar ' + bits + boolvar0 ') = sgn(boolvar ' + bits) + boolvar0 '
Proof step 21:
false ↔ ¬ true, j % 2 = 0, 0 ≤ j, 0 < j, ∀ j0. i→n(j0) < i→n(j) → 0 ≤ j0 → uint2bits(j0 + 1) = sgn(false ' + uint2bits(j0) +1) ⊦ uint2bits(j / 2) + true ' = sgn(false ' + uint2bits(j / 2)) + true ', j = 1

Rule argument

seq: boolvar ↔ ¬ boolvar0 ⊦ sgn(boolvar ' + bits + boolvar0 ') = sgn(boolvar ' + bits) + boolvar0 ' subst: [boolvar0, bits, boolvar] → [true, uint2bits(j / 2), false] rotate: F spec: bitopsaux inst: name: sgn-last-01

Additional information

Used terms: true, uint2bits(j / 2), false