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Proof step 2 from proof uint2bits-succ (previous step)

0 ≤ j ⊦ uint2bits(j + 1) = sgn(false ' + uint2bits(j) +1)

User applied rule induction

And obtained the following new goals

Proof step 3:
0 ≤ j, ∀ j0. i→n(j0) < i→n(j) → 0 ≤ j0 → uint2bits(j0 + 1) = sgn(false ' + uint2bits(j0) +1) ⊦ uint2bits(j + 1) = sgn(false ' + uint2bits(j) +1)

Rule argument

indvar: i→n(j) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(j)