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Proof step 22 from proof uint2bits-succ (previous step)

j % 2 = 0, 0 ≤ j, 0 < j, ∀ j0. i→n(j0) < i→n(j) → 0 ≤ j0 → uint2bits(j0 + 1) = sgn(false ' + uint2bits(j0) +1) ⊦ j = 1, uint2bits(j / 2) = sgn(false ' + uint2bits(j / 2))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ 0 ≤ j → sgn(false ' + uint2bits(j)) = uint2bits(j)

Rule argument

name: uint2bits-sgn-false rotate: F subst: [j] → [j / 2]

Additional information

Used simplifier rules: ⊦ 0 ≤ i / 2 ↔ ~1 ≤ i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j; Used terms: j / 2