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Proof step 1 from proof uint2bits-zero-01 (conclusion)

0 ≤ i ⊦ uint2bits(i) = false ' ↔ i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
uint2bits(i) = false ', 0 < i ⊦ i = 0

Rule argument

Additional information

Used simplifier rules: uint2bits-zero: ⊦ uint2bits(0) = false ';% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ boolvar ' = boolvar0 ' ↔ boolvar ↔ boolvar0;