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Proof step 1 from proof uint2int-rest (conclusion)

⊦ 0 < i → bits2int(uint2bits(i).rest) = i - 2 ^ (n→i(# uint2bits(i)) - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ i = bits2int(uint2bits(i).rest) + 2 ^ (n→i(# uint2bits(i)) - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j;