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Proof step 24 from proof uint2int-rest (previous step)

0 < 2 + n→i(# bits), uint2bits(i) = false ' + true ' + bits, 2 ^ (2 + n→i(# bits))-1 * 2 = 1 + bits2uint(bitsinvert(bits)) + 2 ^ (1 + n→i(# bits)) + i, 0 < i ⊦ 2 ^ (1 + n→i(# bits)) = 1 + bits2uint(bitsinvert(bits)) + i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 1 * i = i;% ⊦ (* i2) * i = i + j0 ↔ (i2 - 1) * i = j0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* i) + i0 - (* j) = (i - j) + i0;% ⊦ i -1 = i - 1;% ⊦ i + j = j + i;