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Proof step 4 from proof uint2int-rest (previous step)

¬(uint2bits(i).rest.first ∧ uint2bits(i).rest ≠ []), 0 < i ⊦ i = bits2int(uint2bits(i).rest) + 2 ^ (n→i(# uint2bits(i)) - 1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: uint2bits-second: ⊦ 0 < i → uint2bits(i).rest.first;%uint2bits-rest: ⊦ 0 < i → uint2bits(i).rest ≠ [];