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Proof step 6 from proof uint2int-rest (previous step)

0 < i ⊦ 2 ^ (n→i(# uint2bits(i)) - 1) = i + bits2uint((false ' + bitsinvert(uint2bits(i).rest.rest))+1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ bits ≠ [] → bits2uint(bits +1) = bits2uint(bits) + 1
Proof step 8:
false ' + bitsinvert(uint2bits(i).rest.rest) ≠ [], 0 < i ⊦ 2 ^ (n→i(# uint2bits(i)) - 1) = i + bits2uint(false ' + bitsinvert(uint2bits(i).rest.rest)) + 1

Rule argument

name: bits2uint-succ rotate: F subst: [bits] → [false ' + bitsinvert(uint2bits(i).rest.rest)]

Additional information

Used simplifier rules: ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ boolvar ' ≠ [];% ⊦ bitsinvert(bits) = [] ↔ bits = [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: false ' + bitsinvert(uint2bits(i).rest.rest)