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Proof step 9 from proof uint2int-rest (previous step)

0 < i ⊦ 2 ^ (n→i(# uint2bits(i)) - 1) = 1 + bits2uint(bitsinvert(uint2bits(i).rest.rest)) + i

User applied rule insert lemma

And obtained the following new goals

Proof step 10:
0 < i ⊦ ∃ bits. uint2bits(i) = false ' + true ' + bits
Proof step 11:
∃ bits. uint2bits(i) = false ' + true ' + bits, 0 < i ⊦ 2 ^ (n→i(# uint2bits(i)) - 1) = 1 + bits2uint(bitsinvert(uint2bits(i).rest.rest)) + i

Rule argument

name: uint2bits-expos0 subst: [i] → [i]

Additional information

Used terms: i