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Proof step 1 from proof uint2uint-inv (conclusion)

0 < i ⊦ bits2uint(bitsinvert(uint2bits(i))) = 2 ^ n→i(# uint2bits(i)) - i + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ 2 ^ n→i(# uint2bits(i)) = bits2uint(bitsinvert(uint2bits(i))) + i + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j;