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Proof step 3 from proof all_prime_divisors-div (previous step)

i | j ∧ prime(i) ∧ 0 < j, ∀ j0, i. i→n(j0) < i→n(j) → i | j0 ∧ prime(i) ∧ 0 < j0 → all_prime_divisors(j0 / i) = all_prime_divisors(j0) -1l i ⊦ all_prime_divisors(j / i) = all_prime_divisors(j) -1l i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information