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Proof step 2 from proof coprimes-max (previous step)

0 < i, 1 < i, i ≤ max(coprimes(i)), 1 < max(coprimes(i)), 0 < max(coprimes(i)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ coprimes(i) = filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))
Proof step 4:
0 < i, 1 < i, i ≤ max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))), 1 < max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))), 0 < max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) ⊦

Rule argument

spec: inst: name: coprimes-def seq: ⊦ coprimes(i) = filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)) subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i