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Proof step 8 from proof coprimes-min (previous step)

0 < i ⊦ filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)) ≠ [], min(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)) = [], 0 < i ⊦

Rule argument

Additional information

Used simplifier rules: min-empty: ⊦ min([]) = 0;