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Proof step 10 from proof count-rec (previous step)

i1 + i = i2 + 1, 0 ≤ i1, ∀ j0, i0. i→n(j0 - i0) < i→n(i1) → i0 ≤ j0 → count-i2j(i0, j0) = i0 ' + count-i2j(i0 + 1, j0) ⊦ count-i2j(i, i2) + (i2 + 1)' = i ' + count-i2j(i + 1, i2 + 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: intlist inst: name: counti2j-rec seq: ⊦ i ≤ j → count-i2j(i, j) = count-i2j(i, j - 1) + j subst: [j, i] → [i2 + 1, i + 1] flags: rewrite, current

Additional information

Used terms: i2 + 1, i + 1