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Proof step 1 from proof countFun-base-03 (conclusion)

⊦ countFun(0, ~1, intfun) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: countFun-base seq: ⊦ j < i → countFun(i, j, intfun) = [] subst: [intfun, j, i] → [intfun, ~1, 0] flags: rewrite, current

Additional information

Used terms: intfun, ~1, 0