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Proof step 1 from proof countFun-in-01 (conclusion)

⊦ i ≤ i0 ∧ i0 ≤ j → intfun(i0) ∈ countFun(i, j, intfun)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i ≤ i0, i0 ≤ j, i ≤ j ⊦ intfun(i0) ∈ countFun(i, j, intfun)

Rule argument

Additional information

Used simplifier rules: forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs