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Proof step 10 from proof divide-list-at-value (previous step)

j < i, perm(ints0, ints1 + ints), min(i ' + ints) ≤ j, j < min(ints), min(i ' + ints) < i, min(i ' + ints) < min(ints), ints1 = [] ∨ max(ints1) ≤ j ⊦ ints = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ ints ≠ [] → min(i ' + ints) = min(i, min(ints))
Proof step 12:
ints ≠ [], j < i, perm(ints0, ints1 + ints), min(i, min(ints)) ≤ j, j < min(ints), min(i, min(ints)) < i, min(i, min(ints)) < min(ints), ints1 = [] ∨ max(ints1) ≤ j ⊦ ints = []

Rule argument

spec: inst: name: min-rec seq: ⊦ ints ≠ [] → min(i ' + ints) = min(i, min(ints)) subst: [ints, i] → [ints, i] flags: rewrite, current

Additional information

Used terms: ints, i