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Proof step 18 from proof divide-list-at-value (previous step)

perm(ints0, ints1 + ints), i ≤ j, j < max(i ' + ints1), max(ints1) ≤ j, i < max(i ' + ints1), max(ints1) < max(i ' + ints1), ints = [] ∨ j < min(ints) ⊦ ints1 = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ ints ≠ [] → max(i ' + ints) = max(i, max(ints))
Proof step 20:
ints1 ≠ [], perm(ints0, ints1 + ints), i ≤ j, j < max(i, max(ints1)), max(ints1) ≤ j, i < max(i, max(ints1)), max(ints1) < max(i, max(ints1)), ints = [] ∨ j < min(ints) ⊦ ints1 = []

Rule argument

spec: inst: name: max-rec seq: ⊦ ints ≠ [] → max(i ' + ints) = max(i, max(ints)) subst: [ints, i] → [ints1, i] flags: rewrite, current

Additional information

Used terms: ints1, i