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Proof step 3 from proof divide-list-at-value (previous step)

⊦ ∃ ints, ints0. ints + ints0 = [] ∧ (ints = [] ∨ max(ints) ≤ j) ∧ (ints0 = [] ∨ j < min(ints0))

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: [], []

Additional information

Used simplifier rules: Nil: ⊦ [] + ints = ints; from specification list[intlista]%a: ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1; from specification list[intlista] Used terms: [], []