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Proof step 8 from proof euler-phi-prime (previous step)

1 ≤ i - 1, prime(i), prime(i) ⊦ i = n→i(i→n(i - 1 - 1) + 1) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%sub-ls-01: ⊦ i < j - i0 ↔ i + i0 < j; from specification int-abs%leone: ⊦ 1 ≤ i ↔ 0 < i; from specification int-abs%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%ini2-abs: ⊦ n→i(i→n(i)) = abs(i); from specification intnat%n2i-add: ⊦ n→i(m + n) = n→i(m) + n→i(n); from specification intnat%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%sub-sub: ⊦ i - j - i0 = i - j + i0; from specification int-abs