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Proof step 1 from proof max-app-ls-01 (conclusion)

⊦ max(ints1 + ints0) < max(ints1) ↔ ints1 = [] ∧ max(ints0) < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
max(ints1 + ints0) < max(ints1) ⊦ ints1 = [] ∧ max(ints0) < 0

Rule argument

Additional information

Used simplifier rules: max-empty: ⊦ max([]) = 0;%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%a: ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1; from specification list[intlista]%Nil: ⊦ [] + ints = ints; from specification list[intlista]