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Proof step 11 from proof max-app (previous step)

max(ints1 + ints1) = max(max(ints1), max(ints1)), max(ints1 + ints1 + ints0) = max(max(ints1), max(ints1 + ints0)), ∀ ints0. ints0 = [] ∨ max(ints1 + ints0) = max(max(ints1), max(ints0)) ⊦ ints0 = [], max(i, max(ints1 + ints0)) = max(max(i ' + ints1), max(ints0)), ints1 + ints0 = [], ints1 = []

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 12:
max(ints1 + ints1) = max(max(ints1), max(ints1)), max(ints1 + ints1 + ints0) = max(max(ints1), max(ints1 + ints0)), ints0 = [] ∨ max(ints1 + ints0) = max(max(ints1), max(ints0)), ∀ ints0. ints0 = [] ∨ max(ints1 + ints0) = max(max(ints1), max(ints0)) ⊦ ints0 = [], max(i, max(ints1 + ints0)) = max(max(i ' + ints1), max(ints0)), ints1 + ints0 = [], ints1 = []

Rule argument

pos: left 3 terms: ints0

Additional information

Used terms: ints0