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Proof step 2 from proof max-app (previous step)

⊦ ints = [], ints0 = [], max(ints + ints0) = max(max(ints), max(ints0))

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ ints0. ints1 = [] ∨ ints0 = [] ∨ max(ints1 + ints0) = max(max(ints1), max(ints0)) ⊦ i + ints1 = [], ints0 = [], max((i + ints1) + ints0) = max(max(i + ints1), max(ints0))

Rule argument

indvar: ints

Additional information

Used simplifier rules: intlist freely generated by [], +;;