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Proof step 3 from proof max-del1-01 (previous step)

∀ i. max(ints0) < max(ints0 -1l i) → ints0 = [] ∨ ints0 = i ' ∧ i < 0, max(i0 + ints0) < max((i0 + ints0) -1l i) ⊦ i0 + ints0 = [], i0 + ints0 = i ' ∧ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
max(i0 ' + ints0) < max((i0 ' + ints0) -1l i), ∀ i. max(ints0) < max(ints0 -1l i) → ints0 = [] ∨ ints0 = i ' ∧ i < 0 ⊦ i0 ' + ints0 = i ' ∧ i < 0

Rule argument

Additional information

Used simplifier rules: a: ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1; from specification list[intlista]%e-01: ⊦ i ' + ints ≠ []; from specification list[intlista]%c: ⊦ i + ints = i ' + ints; from specification list[intlista]