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Proof step 6 from proof max-del1-01 (previous step)

i ≠ i0, max(i0 ' + ints0) < max(i0 ' + (ints0 -1l i)), ∀ i. max(ints0) < max(ints0 -1l i) → ints0 = [] ∨ ints0 = i ' ∧ i < 0 ⊦ i0 ' + ints0 = i ' ∧ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
max(i0 ' + ints0) < max(i0 ' + (ints0 -1l i)), ∀ i. max(ints0) < max(ints0 -1l i) → ints0 = [] ∨ ints0 = i ' ∧ i < 0 ⊦ i = i0, i0 ' + ints0 = i '

Rule argument

Additional information

Used simplifier rules: a: ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1; from specification list[intlista]%c-03: ⊦ i ' = i0 ' + ints ↔ i = i0 ∧ ints = []; from specification list[intlista]