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Proof step 22 from proof max-del1 (previous step)

i0 < max(ints0), i < max(ints0), ∀ i. i < max(ints0) → max(ints0 -1l i) = max(ints0) ⊦ i = i0, ints0 = [], ints0 = i ', max(i0, max(ints0 -1l i)) = max(ints0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ ¬ j < i → max(j, i) = j
Proof step 24:
¬ ¬ i0 < max(ints0 -1l i), i0 < max(ints0), i < max(ints0), ∀ i. i < max(ints0) → max(ints0 -1l i) = max(ints0) ⊦ i = i0, ints0 = [], ints0 = i ', max(i0, max(ints0 -1l i)) = max(ints0)
Proof step 26:
¬ i0 < max(ints0 -1l i), i0 < max(ints0), i < max(ints0), ∀ i. i < max(ints0) → max(ints0 -1l i) = max(ints0) ⊦ i = i0, ints0 = [], ints0 = i ', i0 = max(ints0)

Rule argument

spec: int-min inst: name: Max-left seq: ⊦ ¬ j < i → max(j, i) = j subst: [i, j] → [max(ints0 -1l i), i0] flags: rewrite

Additional information

Used terms: max(ints0 -1l i), i0