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Proof step 3 from proof max-del1 (previous step)

∀ i. i < max(ints0) → max(ints0 -1l i) = max(ints0), i < max(i0 + ints0) ⊦ max((i0 + ints0) -1l i) = max(i0 + ints0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i < max(i0 ' + ints0), ∀ i. i < max(ints0) → max(ints0 -1l i) = max(ints0) ⊦ max((i0 ' + ints0) -1l i) = max(i0 ' + ints0)

Rule argument

Additional information

Used simplifier rules: c: ⊦ i + ints = i ' + ints; from specification list[intlista]