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Proof step 2 from proof max-is-max (previous step)

i ∈ ints, max(ints) < i ⊦ ints = []

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints))
Proof step 4:
ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints)), i ∈ ints, max(ints) < i ⊦ ints = []

Rule argument

spec: inst: name: max-def seq: ⊦ ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints)) subst: [ints] → [ints] flags: current, []

Additional information

Used terms: ints