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Proof step 5 from proof max-le-rec (previous step)

0 < j ⊦ ints = [], max(i, max(ints)) ≤ j ↔ i ≤ j ∧ max(ints) ≤ j

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-min inst: name: Max-left seq: ⊦ ¬ j < i → max(j, i) = j subst: [i, j] → [max(ints), i] flags: rewrite

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%transitivity: ⊦ i < i0 ∧ i0 < i1 → i < i1; (forward) from specification oelem[intlista]%lenls: ⊦ i ≤ j → ¬ j < i; from specification int-abs%Max-right: ⊦ j < i → max(j, i) = i; from specification int-min%max-a: ⊦ max(i, max(j, j0)) = max(max(i, j), j0); from specification int-min%max-c: ⊦ max(i, j) = max(j, i); from specification int-min Used terms: max(ints), i