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Proof step 7 from proof max-perm (previous step)

perm(ints1, ints0 -1l i), i ∈ ints0, ∀ ints0. perm(ints1, ints0) → max(ints1) = max(ints0) ⊦ max(i ' + ints1) = max(ints0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ ints ≠ [] → max(i ' + ints) = max(i, max(ints))
Proof step 9:
¬ ints1 ≠ [], perm(ints1, ints0 -1l i), i ∈ ints0, ∀ ints0. perm(ints1, ints0) → max(ints1) = max(ints0) ⊦ max(i ' + ints1) = max(ints0)
Proof step 12:
ints1 ≠ [], perm(ints1, ints0 -1l i), i ∈ ints0, ∀ ints0. perm(ints1, ints0) → max(ints1) = max(ints0) ⊦ max(i, max(ints1)) = max(ints0)

Rule argument

spec: inst: name: max-rec seq: ⊦ ints ≠ [] → max(i ' + ints) = max(i, max(ints)) subst: [ints, i] → [ints1, i] flags: rewrite, current

Additional information

Used terms: ints1, i