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Proof step 12 from proof max-rec (previous step)

i ≤ max(i ' + ints), max(ints) ≤ max(i ' + ints), ∀ i0. i0 ∈ ints → i0 ≤ max(i ' + ints), ∀ i. i ∈ ints → i ≤ max(ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

User applied rule all left

And obtained the following new goals

Proof step 13:
i ≤ max(i ' + ints), max(ints) ≤ max(i ' + ints), ∀ i0. i0 ∈ ints → i0 ≤ max(i ' + ints), i ∈ ints → i ≤ max(ints), ∀ i. i ∈ ints → i ≤ max(ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Rule argument

pos: left 4 terms: i abort: F discard: F computed: F

Additional information

Used terms: i