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Proof step 14 from proof max-rec (previous step)

i ≤ max(i ' + ints), max(ints) ≤ max(i ' + ints), ∀ i0. i0 ∈ ints → i0 ≤ max(i ' + ints), i ∈ ints → i ≤ max(ints), max(i ' + ints) ∈ ints → max(i ' + ints) ≤ max(ints), ∀ i. i ∈ ints → i ≤ max(ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
i ≤ max(i ' + ints), max(ints) ≤ max(i ' + ints), ∀ i0. i0 ∈ ints → i0 ≤ max(i ' + ints), i ∈ ints → i ≤ max(ints), ∀ i. i ∈ ints → i ≤ max(ints), max(i ' + ints) ∈ ints → max(ints) = max(i ' + ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Rule argument

Additional information

Used simplifier rules: anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs