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Proof step 8 from proof max-rec (previous step)

∀ i. i ∈ ints → i ≤ max(ints), ∀ i0. i0 = i ∨ i0 ∈ ints → i0 ≤ max(i ' + ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

User applied rule all left

And obtained the following new goals

Proof step 9:
∀ i. i ∈ ints → i ≤ max(ints), i = i ∨ i ∈ ints → i ≤ max(i ' + ints), ∀ i0. i0 ∈ ints → i0 ≤ max(i ' + ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Rule argument

pos: left 2 terms: i abort: F discard: F computed: T

Additional information

Used terms: i