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Proof step 12 from proof min-del-nlz-01 (
previous step
)
0 < min(i, min(ints0)), 0 < min(ints0), min(ints0 -l i) < 0, min(ints0 -l i) < min(i, min(ints0)), min(ints0 -l i) < min(ints0), ∀ i0. ¬ min(ints0 -l i0) < 0 ⊦ ints0 = []
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 6 terms: i
Additional information
Used terms: i