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Proof step 2 from proof min-del-nlz (previous step)

min(ints -l i0) < 0, min(ints -l i0) < min(i ' + ints), 0 < min(i ' + ints) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ints ≠ [] → min(i ' + ints) = min(i, min(ints))
Proof step 4:
ints ≠ [], min(ints -l i0) < 0, min(ints -l i0) < min(i, min(ints)), 0 < min(i, min(ints)) ⊦

Rule argument

spec: inst: name: min-rec seq: ⊦ ints ≠ [] → min(i ' + ints) = min(i, min(ints)) subst: [ints, i] → [ints, i] flags: rewrite, current

Additional information

Used simplifier rules: min-empty: ⊦ min([]) = 0;%del-e: ⊦ [] -l i = []; from specification list-del[intlista] Used terms: ints, i