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Proof step 2 from proof min-in-nls (previous step)

j < min(i ' + ints), i < j, i < min(i ' + ints) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: min-rec seq: ⊦ ints ≠ [] → min(i ' + ints) = min(i, min(ints)) subst: [ints, i] → [ints, i] flags: rewrite, current

Additional information

Used simplifier rules: min-one: ⊦ min(i ') = i;%min-03: ⊦ ¬ i < min(i, j); from specification int-min%min-a: ⊦ min(i, min(j, j0)) = min(min(i, j), j0); from specification int-min%min-c: ⊦ min(i, j) = min(j, i); from specification int-min%app: ⊦ ints + [] = ints; from specification list[intlista]%a: ⊦ (ints + ints0) + ints1 = ints + ints0 + ints1; from specification list[intlista]%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1 Used terms: ints, i