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Proof step 2 from proof min-in-not-ls (previous step)

i ∈ ints, i < min(ints) ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ ints ≠ [] → min(ints) ∈ ints ∧ (∀ i. i ∈ ints → min(ints) ≤ i)
Proof step 4:
ints ≠ [] → min(ints) ∈ ints ∧ (∀ i. i ∈ ints → min(ints) ≤ i), i ∈ ints, i < min(ints) ⊦

Rule argument

spec: inst: name: min-def seq: ⊦ ints ≠ [] → min(ints) ∈ ints ∧ (∀ i. i ∈ ints → min(ints) ≤ i) subst: [ints] → [ints] flags: current, []

Additional information

Used terms: ints