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Proof step 18 from proof min-rec (previous step)

¬ i < min(ints), min(i ' + ints) ≤ i, ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = min(ints)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
min(i ' + ints) ≤ i, min(ints) ≤ i, ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = min(ints)

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs