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Proof step 21 from proof min-rec (previous step)

min(i ' + ints) ≤ i, min(ints) ≤ i, min(i ' + ints) < min(ints), min(i ' + ints) < i, ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = min(ints)

User applied rule all left

And obtained the following new goals

Proof step 22:
min(i ' + ints) ≤ i, min(ints) ≤ i, min(i ' + ints) < min(ints), min(i ' + ints) < i, ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, min(i ' + ints) ∈ ints → min(ints) ≤ min(i ' + ints), ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = min(ints)

Rule argument

pos: left 6 terms: min(i ' + ints) abort: F discard: F computed: T

Additional information

Used terms: min(i ' + ints)