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Proof step 5 from proof min-rec (previous step)

∀ i0. i0 = i ∨ i0 ∈ ints → min(i ' + ints) ≤ i0 ⊦ ints = [], min(i ' + ints) = min(i, min(ints))

User applied rule all left

And obtained the following new goals

Proof step 6:
i = i ∨ i ∈ ints → min(i ' + ints) ≤ i, ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0 ⊦ ints = [], min(i ' + ints) = min(i, min(ints))

Rule argument

pos: left 1 terms: i abort: F discard: F computed: T

Additional information

Used terms: i