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Proof step 7 from proof primes-perm-01 (previous step)

perm(ints, ints1 + ints0), ∀ i. i ∈ ints → prime(i), i ∈ ints1 ⊦ prime(i)

User applied rule all left

And obtained the following new goals

Proof step 8:
perm(ints, ints1 + ints0), i ∈ ints → prime(i), i ∈ ints1 ⊦ prime(i)

Rule argument

pos: left 2 terms: i abort: F discard: T computed: T

Additional information

Used terms: i