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Proof step 12 from proof primes-rec (previous step)

prime(i), ∀ i. (∀ i0. i0 = i ∨ i0 ∈ ints0 → prime(i0)) → prime(i) ∧ (∀ i. i ∈ ints0 → prime(i)), ∀ i2. i2 = i0 ∨ i2 ∈ ints0 → prime(i2) ⊦ prime(i0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: i0

Additional information

Used terms: i0