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Proof step 4 from proof product-del1-01 (previous step)

i ∈ ints ∧ i ≠ 0 → Π(ints -1l i) * i = Π ints, i ∈ ints ⊦ i = 0, Π(ints -1l i) = Π ints / i

User applied rule case distinction

And obtained the following new goals

Proof step 5:
Π(ints -1l i) * i = Π ints, i ∈ ints ⊦ i = 0, Π(ints -1l i) = Π ints / i

Rule argument

pos: left 1

Additional information