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Proof step 1 from proof product-equal-01 (conclusion)

¬ dups(ints), ¬ dups(ints0), ∀ i. i ∈ ints ↔ i ∈ ints0 ⊦ Π ints = Π ints0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
∀ i. i ∈ ints ↔ i ∈ ints0 ⊦ Π ints = Π ints0, dups(ints), dups(ints0)

Rule argument

Additional information